4x^2-0.04=0

Solution for 4x^2-0.04=0 equation:

4x^2-0.04=0

a = 4; b = 0; c = -0.04;
Δ = b2-4ac
Δ = 02-4·4·(-0.04)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.64}}{2*4}=\frac{0-\sqrt{0.64}}{8}
=-\frac{\sqrt{}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.64}}{2*4}=\frac{0+\sqrt{0.64}}{8}
=\frac{\sqrt{}}{8}
$